2x^2+3x-5=3

Solution for 2x^2+3x-5=3 equation:

2x^2+3x-5=3

We move all terms to the left:

2x^2+3x-5-(3)=0

We add all the numbers together, and all the variables

2x^2+3x-8=0

a = 2; b = 3; c = -8;
Δ = b2-4ac
Δ = 32-4·2·(-8)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{73}}{2*2}=\frac{-3-\sqrt{73}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{73}}{2*2}=\frac{-3+\sqrt{73}}{4}
$